Zoe had these five numbered cards:
How many five-digit numbers can she make that are divisible by 9 without having a remainder?
A Mathematics problem solving weblog.
Zoe had these five numbered cards:
How many five-digit numbers can she make that are divisible by 9 without having a remainder?
I think, therefore I am 
The number 9 has a cool divisibility trick, if the sum of all the digits is divisible by 9, than the number is divisible by 9.
The sum of the above numbers is 27 – so whatever order you place the digits they will be divisible by 9.
The answer is 120 (5*4*3*2*1)